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Exam Code:
1z0-420Exam Name: Oracle Fusion HCM: Talent Management 2014 Essentials
One year free update, No help, Full refund!
1z0-420 Study Materials Total Q&A: 79 Questions and Answers
Last Update: 11-05,2015
1z0-420 Exam Tests Detail: 1z0-420 Study Materials
Exam Code:
1z0-061Exam Name: Oracle Database 12c: SQL Fundamentals
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1z0-061 PDF VCE Total Q&A: 75 Questions and Answers
Last Update: 11-05,2015
1z0-061 Actual Test Detail: 1z0-061 PDF VCE
NO.1 View the Exhibit for the structure of the student and faculty
tables.
You need to display the faculty name followed by the number of
students handled by the faculty at
the base location.
Examine the
following two SQL statements:
Which statement is true regarding the
outcome?
A. Both statements 1 and 2 execute successfully and give different
results.
B. Only statement 2 executes successfully and gives the required
result.
C. Both statements 1 and 2 execute successfully and give the same
required result.
D. Only statement 1 executes successfully and gives the
required result.
Answer: C
1z0-061 test answers
NO.2 In the
customers table, the CUST_CITY column contains the value 'Paris' for
the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would
be the outcome?
A. Abigail Pa
B. Abigail IS
C. An error message
D.
Abigail PA
Answer: A
1z0-061 Exam Questions 1z0-061 Exam
PDF
NO.3 Evaluate the following SQL statement:
Which statement
is true regarding the outcome of the above query?
A. It produces an error
because positional notation cannot be used in the order by clause with
set
operators.
B. It produces an error because the order by clause should
appear only at the end of a compound
query-that is, with the last select
statement.
C. It executes successfully but ignores the order by clause
because it is not located at the end of the
compound statement.
D. It
executes successfully and displays rows in the descending order of
PROMO_CATEGORY .
Answer: B
NO.4 Examine the structure proposed for the
transactions table:
Which two statements are true regarding the creation and
storage of data in the above table
structure?
A. The TRANS_VALIDITY column
would have a maximum size of one character.
B. The CUST_STATUS column would
store exactly one character.
C. The CUST_CREDIT_LIMIT column would not be
able to store decimal values.
D. The TRANS_DATE column would be able to store
day, month, century, year, hour, minutes,
seconds, and fractions of
seconds
E. The CUST_STATUS column would give an error.
F. The
TRANS_VALIDITY column would give an error.
Answer: B,F
1z0-061 Study
Guide 1z0-061 Exam PDF
Explanation:
VARCHAR2(size)Variable-length
character data (A maximum size must be specified:
minimum size is 1; maximum
size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size
bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p,
s)] Number having precision p and scale s (Precision is the total number
of
decimal digits and scale is the number of digits to the right of the
decimal point; precision
can range from 1 to 38, and scale can range from -84
to 127.)
DATE Date and time values to the nearest second between January 1,
4712 B.C., and
December 31, 9999 A.D.
NO.5 Which normal form is a
table in if it has no multi-valued attributes and no
partial
dependencies?
A. First normal form
B. Fourth normal form
C.
Third normal form
D. Second normal form
Answer: D
1z0-061 Exam
Tests 1z0-061
Practice Questions
NO.6 You need to create a table for a banking
application. One of the columns in the table has the
following
requirements:
1. You want a column in the table to store the duration of the
credit period.
2) The data in the column should be stored in a format such
that it can be easily added and
subtracted with date data type without using
conversion functions.
3) The maximum period of the credit provision in the
application is 30 days.
4) The interest has to be calculated for the number
of days an individual has taken a credit for.
Which data type would you use
for such a column in the table?
A. NUMBER
B. DATE
C. TIMESTAMP
D.
INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D
1z0-061
Bootcamp
NO.7 View the Exhibit and examine the structure of the
product, component, and PDT_COMP
tables.
In product table, PDTNO is the
primary key.
In component table, COMPNO is the primary key.
In PDT_COMP
table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key
referencing
PDTNO in product table and COMPNO is the foreign key referencing
the COMPNO in component
table.
You want to generate a report listing the
product names and their corresponding component names,
if the component names
and product names exist.
Evaluate the following query:
SQL>SELECT
pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING
(pdtno) ____________ component USING (compno)
WHERE compname IS NOT
NULL;
Which combination of joins used in the blanks in the above query gives
the correct output?
A. FULL OUTER JOIN; FULL OUTER JOIN
B. RIGHT OUTER
JOIN; LEFT OUTER JOIN
C. JOIN; JOIN
D. LEFT OUTER JOIN; RIGHT OUTER
JOIN
Answer: B
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