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NO.1 Which statement is true about the take method defined in the WatchService interface?
A. Retrieves and removes the next watch key, or returns null of none are present.
B. Retrieves and removes the next watch key. If a queued key is not immediately available,
the program
waits for the specified wait time.
C. Retrieves and removes the next watch key: waits if no key is yet present.
D. Retrieves and removes all pending events for the watch key, returning a list of the events
that were
retrieved.
Answer: C

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NO.2 Given a resource bundle MessageBundle, what is the name of the default bundle file?
A. MessageBundle.profile
B. MessageBundle.xml
C. MessageBundle.java
D. MessageBundle.properties
Answer: D

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NO.3 What design pattern does the Drivermanager.getconnection () method characterize?
A. DAO
B. Factory
C. Singleton
D. composition
Answer: B

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NO.4 Given three resource bundles with these values set for menu1: ( The default resource
bundle is
written in US English.)
English US resource Bundle Menu1 = small
French resource Bundle Menu1 = petit
Chinese Resource Bundle Menu = 1
And given the code fragment:
Locale.setDefault (new Locale("es", "ES")); // Set default to Spanish and Spain loc1 =
Locale.getDefault();
ResourceBundle messages = ResourceBundle.getBundle ("messageBundle", loc1);
System.out.println
(messages.getString("menu1")); What is the result?
A. No message is printed
B. petit
C. :
D. Small
E. A runtime error is produced
Answer: E

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NO.5 Given the code fragment:
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the
file info.txt to
the destination directory, even if a file by the same name already exists in the destination
directory?
A. try {FileChannel in = new FileInputStream(source).getChannel(); FileChannel out = new
FileOutputStream(dest).getChannel (); in.transferTo (0, in.size(), out);
B. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
C. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
D. try {Files.move(Paths.get(source),Paths.get(dest));
E. try {BufferedReader br = Files.newBufferedReader(Paths.get(source), Charset.forName
("UTF8"));
BufferedWriter bw = Files.newBufferedWriter (Paths.get(dest), Charset.forName ("UTF-8"));
String record
= ""; while ((record = br.readLine()) != null){ bw.write (record); bw.newLine(); }
Files.delete(Paths.get(source));
Answer: B,D

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NO.6 Which two statements are true about the walkFileTree method of the files class?
A. The file tree traversal is breadth-first with the given FileVisitor invoked for each file
encountered.
B. If the file is a directory, and if that directory could not be opened, the postVisitFileFailed
method is
invoked with the I/O exception.
C. The maxDepth parameter s value is the maximum number of directories to visit.
D. By default, symbolic links are not automatically followed by the method.
Answer: C,D

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NO.7 Given the fragment:
public class CustomerApplication {
public static void main (String [] args) {
CustomerDAO custDao = new CustomerDAOMemoryImp1 ();
// . . . other methods
} }
Which two valid alternatives to line 3 would decouple this application from a specific
implementation of
customerDAO?
A. CustomerDAO custDao = new customerDAO();
B. CustomerDAO custDao = (CustomerDAO) new object();
C. CustomerDAO custDao = CustomerDAO.getInstance();
D. CustomerDAO custDao = (CustomerDAO) new CustomerDAOmemoryImp1();
E. CustomerDAO custDao = CustomerDAOFactory.getInstance();
Answer: C,E

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NO.8 Given:
import java.util.*; public class StringApp { public static void main (String [] args) { Set <String>
set = new
TreeSet <> (); set.add("X"); set.add("Y"); set.add("X"); set.add("Y"); set.add("X"); Iterator
<String> it =
set.iterator (); int count = 0; while (it.hasNext()) { switch (it.next()){ case "X":
System.out.print("X "); break;
case "Y": System.out.print("Y "); break; } count++; } System.out.println ("\ncount = " + count);
} }
What is the result?
A. X X Y X Y count = 5
B. X Y X Y count = 4
C. X Y count = s
D. X Y count = 2
Answer: D

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